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Dalton's Law of Partial Pressures

A certain qua...

Question

A certain quantity of a gas occupies a volume of 0.1 litre . When collected over water at 288 K and 0.92 pressure. The same gas occupied a volume of 0.085 litres at S.T.P in dry condition. Calculate aqueous tension at 28 K.

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Solution

$P_{d r y g a s} = P_{o b s e r v e d} - a q u e o u s t e n s i o n$
$A q u e o u s t e n s i o n = P_{o b s e r v e d} - P_{d r y g a s}$
$P_{o b s e r v e d} = 0.92$
$P_{d r y g a s} = ?$
According to combine gas law
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
[Experimental condition STP condition]
pressure of dry gas
$P_{1} = \frac{P_{2} V_{2}}{T_{2}} \times \frac{T_{1}}{V_{1}}$
= $\frac{1 \times 0.085}{- 245} \times \frac{273}{0.1}$
= $0.94714$
Aqueous tension= $P_{o b s e r v e d} - P_{d r y g a s}$
= $0.92 - 0.94714$ atm= $- 0.02714$

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