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Question

A certain reaction has value of Kp=0.03 at 100 K and ΔrHo=921.2 cal mol1.
Calculate the value of Kp at 200 K.

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Solution

Given, T1=100KT2=200K

ΔrHo=921.2 calKp1=0.03

The Van't Hoff equation is given as:
logKp2Kp1=ΔHo2.303R[T2T1T1T2]
putting the values we get,
logKp20.03=921.22.303×2[200100200×100]
logKp20.03=921.24.606×1200=921.2921.2

logKp20.03=1
Kp20.03=101
Kp2=0.03×10=0.3

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