A certain soil has the following properties, Gs=2.71,n=40% and w=20% .The degree of saturation of the soil rounded off to the nearest percentage is _______ .
81
Open in App
Solution
The correct option is A 81 Gs=2.71
n = 40%
w = 20%
Weknowthat,eS=WGs
⇒S=wGse
e=n1−n=0.40.6
⇒S=0.2×2.710.40.6=0.813
Degree of saturation is 81.3%, Ans is 81% .