Question

A certain transverse sinusoidal wave of wavelength $20cm$ is moving in the positive $x-$ direction. The transverse velocity of the particle at $x=0$ as a function of time is shown. The amplitude of the motion is

• A. $\frac{5}{\pi }cm$
• B. $\frac{\pi }{2}cm$
• C. $\frac{10}{\pi }cm$
• D. $2\pi cm$

Answer 1

The correct option is C $\frac{10}{\pi }cm$

$\lambda =20cm,T=4s$

From the figure

$V_{max}=5cm/s=A\omega A=\frac{5}{\omega }A=\frac{5}{2\pi /T}=\frac{5\times 4}{2\pi }[A=\frac{10}{\pi }cm]$

Hence option (C) is correct.