A certain weight of pure CaCO3 is made to react completely with 200 mL of a HCl solution to give 224 mL of CO2 gas at STP. The normality of the HCl is:
A
0.05N
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B
0.1N
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C
1.0N
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D
0.2N
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Solution
The correct option is B0.1N
The balanced reaction is as follows:
CaCO3+2HCl⟶CO2+CaCl2
224 mL of CO2 is 0.01 moles at STP.
Hence, number of moles of CaCO3 is 0.01.
Hence, 0.02 moles of HCl is needed for complete reaction.