Question

(a) $\left(C{H}_3{)}_{3}CCH\right(OH)C{H}_3\stackrel{conc.H_{2}S{O}_4}{⟶}$
(b) $\left(C{H}_3{)}_{2}CHCH\right(Br)C{H}_3\stackrel{alc.KOH}{⟶}$

Choose the correct statement regarding the given reactions:

• A. Only (a) gives saytzeff product
• B. Only (b) gives saytzeff product
• C. Both (a) and (b) gives saytzeff product
• D. Both (a) and (b) gives hofmann product

Answer 1

The correct option is C Both (a) and (b) gives saytzeff product

Saytzeff or Zaitsev Rule states that the more substituted alkene will be the major product.

Both reactions (a) and (b) gives more substituted saytzeff product.

In (a), the reaction goes through stable carbocation intermediate and leads to formation of more substituted alkene compound.


In (b), due to smaller size of the base, it abstract proton from steric site to form a more substituted and stable alkene.