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Question

A) CH3CH2CH2
B) CH3CH|FCH2
C) CH3CH|BrCH2
D) CH3CH|ClCH2
Arrange the following carbocations in decreasing order of their stability:

A
A>B>C>D
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B
A>C>D>B
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C
B>A>C>D
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D
D>B>C>A
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Solution

The correct option is D A>C>D>B
Stability of carbocation1I effect
So, an order of stability will be,
A>C>D>B
Fluorine has a maximum I effect, so it will be unstable carbocation.

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