A chamber of constant volume contain hydrogen gas. When the chamber is immersed in a bath of melting ice ( $0^{o} C$ ) the pressure of the gas is $800$ torr. What pressure will be indicated when the chamber is brought to $100^{o} C$ ?

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Solution

We are doing the process at constant volume.
Applying Gay Lussac's law
$\begin{matrix} \frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} P_{2} = \frac{860}{273.15} \times 373.15 P_{2} = 1174.84 t o r r \end{matrix}$

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A chamber of constant volume contain hydrogen gas. When the chamber is immersed in a bath of melting ice (0oC) the pressure of the gas is 800 torr. What pressure will be indicated when the chamber is brought to 100oC?

We are doing the process at constant volume.Applying Gay Lussac's lawP1T1=P2T2P2=860273.15×373.15P2=1174.84torr

A chamber of constant volume contain hydrogen gas. When the chamber is immersed in a bath of melting ice ( $0^{o} C$ ) the pressure of the gas is $800$ torr. What pressure will be indicated when the chamber is brought to $100^{o} C$ ?

We are doing the process at constant volume.
Applying Gay Lussac's law
$\begin{matrix} \frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} P_{2} = \frac{860}{273.15} \times 373.15 P_{2} = 1174.84 t o r r \end{matrix}$