A change of 8.0 mA in the emitter current brings a change of 7.9 mA in the collector current. The value of $α$ will be

0.96

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0.93

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0.9

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0.99

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Solution

The correct option is D 0.99
The current gain $α$ in a common base amplifier is given by:
$α = \frac{Δ I_{C}}{Δ I_{E}}$

Given: $Δ I_{C} = 7.9 m A; Δ I_{E} = 8.0 m A$

Hence, $α = \frac{7.9}{8.0} = 0.99$

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