A change of $8 m A$ in the emitter current brings a change of $7.9 m A$ in the collector current. The value of $β$ is

79 / 80

No worries! We‘ve got your back. Try BYJU‘S free classes today!

80 / 79

No worries! We‘ve got your back. Try BYJU‘S free classes today!

79

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

80

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $79$
Given that:
$I_{e} = 8 m A$
$I_{c} = 7.9 m A$
In transistors,
$I_{e} = I_{b} + I_{c}$
$Δ I_{e} = Δ I_{b} + Δ I_{c}$
$Δ I_{b} = Δ I_{e} - Δ I_{c}$
$∴ I_{b} = 8 - 7.9 = 0.1 m A$
The current gain in CE mode is
$β = \frac{I_{c}}{I_{b}} = \frac{7.9}{0.1} = 79$

Suggest Corrections

Similar questions

8 m A

7.9 m A

8.0 m A

7.9 m A

α

β

β

80

250

μ A

α

In a common emitter transistor, the current gain is 80. What is the change in collector current, when the change in base current is 250 mA

Join BYJU'S Learning Program