A charge of $2 \times 10^{- 2}$ C moves at 30 revolutions per second in a circle of diameter 80 cm. Find the current linked with the circuit.

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Solution

We know that,

I = $\frac{q}{t}$

The charge in the circuit takes 1 s to complete 30 revolutions.

So for 1 revolution it will take $\frac{1}{30}$ s.

I = $\frac{2 \times 10^{- 2}}{\frac{1}{30}}$ = 0.6 A

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A charge of 2×10−2 C moves at 30 revolutions per second in a circle of diameter 80 cm. Find the current linked with the circuit.

We know that, I = qt The charge in the circuit takes 1 s to complete 30 revolutions. So for 1 revolution it will take 130 s. I = 2×10−2130 = 0.6 A

A charge of $2 \times 10^{- 2}$ C moves at 30 revolutions per second in a circle of diameter 80 cm. Find the current linked with the circuit.

We know that,

I = $\frac{q}{t}$

The charge in the circuit takes 1 s to complete 30 revolutions.

So for 1 revolution it will take $\frac{1}{30}$ s.

I = $\frac{2 \times 10^{- 2}}{\frac{1}{30}}$ = 0.6 A