Question

A charge of $2\times {10}^{-2}$ C moves at 30 revolutions per second in a circle of diameter 80 cm. The current linked with the circuit is:

• A. 0.6 A
• B. 1.6 A
• C. 0.2 A
• D. 1.2 A

Answer 1

The correct option is A

0.6 A

We know that,
I = q/t
Where I is current and q is the quantity of charge flowing by a point in a time period of t
The charge in the circuit takes 1 s to complete 30 revolutions.
So for 1 revolution it will take $\frac{1}{30}s.$

I = $\frac{2\times {10}^{-2}}{\frac{1}{30}}$ = 0.6 A