A charge of 5C experiences a force of 5000N when it is moved in a uniform electric field. The potential difference between two points separated by a distance of 1cm is?

Open in App

Solution

we have the equation
potential difference V = work done / charge = force distance / charge
=fd/q
=(5000110^-2)/5
=10 V

Suggest Corrections

Similar questions

Q. A charge of

5 C

experience a force of

5000 N

when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of

1 c m

Q. A Charge of 3C experiences a force of 3000N when it is moved in a uniform electric field. What is the potential difference between two points separated by a distance of 1cm in the direction of field

Q. A charge

3

coulomb experiences a force

3000 N

when placed in a uniform electric field. The potential difference between two points seperated by a distance of

1 c m

along the field lines is :

Q. When charge of

3

coulomb is placed in a Uniform electric field, it experiences a force of

3000

newton, within this field, potential difference between two points separated by a distance of

1 cm

is (in volt)

In a uniform electric field a charge of $3 C$ experiences a force of $3000 N$ . The potential difference between two points $1 c m$ apart along the electric lines of force will be:

Join BYJU'S Learning Program

A charge of 5C experiences a force of 5000N when it is moved in a uniform electric field. The potential difference between two points separated by a distance of 1cm is?

we have the equation potential difference V = work done / charge = force *distance / charge =f*d/q =(5000*1*10^-2)/5 =10 V

we have the equation
potential difference V = work done / charge = force distance / charge
=fd/q
=(5000110^-2)/5
=10 V