Question

A charge q₀ is distributed uniformly on a ring of radius R.A sphere of equal radius R is constructed with its centre on the circumference of the ring. The electric flux through the surface of the sphere is

Answer 1

Dear Student this is the question of electric flux . flux equals to $\frac{q}{{\epsilon }_0}$ where q is the charge enclosed in the sphere. here in
this case charge enclosed can be find if we can find the ring enclosed in the sphere . ring length enclosed in sphere is

$$\begin{gathered} 2\pi R\times \frac{120}{360}=\frac{2}{3}\pi R \\ nowlinearchrgedensity\gamma =\frac{q_0}{2\pi R} \\ thereforechargeenclosedinsphereis=\frac{q_0}{2\pi R}\times \frac{2}{3}\pi R=\frac{q_0}{3} \\ fluxbysphere=\frac{q_0}{3{\epsilon }_0} \end{gathered}$$
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