A charged cork ball of mass 1 g is suspended on a light string in the presence of a uniform electric field as shown. When →E=(3^i+5^j)×105NC−1, the ball is in equilibrium at θ=37. T is the tension in the string and q is the charge on the ball (Take sin 37 = 0.60 and g=10ms−2)
A
Q = 21 nC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
q = 12 nC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
T=5.55×10−3N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
T=4.55×10−3N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CT=5.55×10−3N T=cosθ+qEy=mg ...........(1) T=sinθ=qEx ⇒T(0.6)=3×105q ⇒q=603×10−5T ⇒q=2×10−6T ⇒T(0.8)+T=10100 ⇒T=5.55×10−3N ⇒q=11.1×10−9C ⇒q=11nC