Summary for Time, Height and Range
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The angle of projection at which the horizontal range and maximum height of projectile are equal is
45∘
θ=tan−1(0.25)
θ=tan−14 or (θ=76∘)
60∘
A stone projected with a velocity u at an angle θ with the horizontal reaches maximum height H1. When it is projected with velocity u at an angle (π2−θ) with the horizontal, it reaches maximum height H2.
The relation between the horizontal range R of the projectile, H1 and H2 is
R=4√H1H2
R=4(H1−H2)
R=4(H1+H2)
R=H21H22
For a projectile, the ratio of maximum height reached to the square of flight time is (g=10ms−2)
5 : 4
5 : 2
5 : 1
10 : 1
A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of 30∘ with the horizontal. The change in momentum (in magnitude) of the body is
24.5 N-s
49.0 N-s
98.0 N-s
50.0 N-s
A stone is just released from the window of a train moving along a horizontal straight track. The stone will hit the ground following
Straight path
Circular path
Parabolic path
Hyperbolic path
A ball is projected upwards from the top of tower with a velocity 50 ms−1 making an angle 30∘ with the horizontal. The height of tower is 70 m. After how many seconds from the instant of throwing will the ball reach the ground
2 s
5 s
7 s
9 s
- 45∘
- 60∘
- 90∘
- 30∘
At what point of a projectile motion acceleration and velocity are perpendicular to each other
At the topmost point
At the point of projection
At the point of drop
Any where in between the point of projection and topmost point
The greatest height to which a man can throw a stone is h. The greatest distance to which he can throw it, will be
h2
2h
3h
h
- 60∘
- 90∘
- 45∘
- 30∘