A popular game in Indian village is goli which is played with small glass balls called golis. The goli of one player is situated at a distance of 2.0 m from the goli of the second player. This second played has to project his goli by keeping the thumb of the left hand at the place of his goli, holding the goli between his two middle fingers and making the throw, if the projected goli hits the goli of the first player, the second player wins. If the height from which the goli projected is 19.6 m from the ground and the goli is to be projected horizontally, with what speed should it be projected so that it directly hits the stationary goli without falling on the ground earlier.

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Solution

The goli moves like a projectivel.

Here, h = 0.196 m

Horizontal distance, x = 2 m

Acceleration, g = 9.8 $m / s^{2}$

Time to reach the ground

t = $\sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 0.196}{9.8}}$

= 0.4 = 0.2 sec

Let horizontal velocity with which it is projected be u m/s

$∴$ x = ut
$\Rightarrow$ u = $\frac{x}{t} = \frac{2}{0.2} = 10 m / s$

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