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Question

During a projectile motion, if the maximum height equals the horizontal range, then the angle of projection with the horizontal is

A
tan1 1
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B
tan1 2
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C
tan1 3
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D
tan1 4
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Solution

The correct option is D tan1 4
We know that,
Range, R=u2sin2θg
Maximum height, Hmax=u2sin2θ2g
According to the question,
R=Hmax
2u2sinθcosθg=u2sin2θ2g
2cosθ=sinθ2
4=tanθ
θ=tan14
So, option D is correct.

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