Question

A charged parallel plate capacitor of distance (d) has $U_0$ energy. A slab of dielectric constant (K) and thickness (d) is then introduced between the plates of the capacitor. The new energy of the system is given by:

• A. K$U_0$
• B. $K^2{U}_0$
• C. $\frac{U_0}{K}$
• D. $\frac{U_0}{K^2}$

Answer 1

The correct option is A K$U_0$

When a dielectric slab is inserted between the the plates of parallel plates capacitor, capacitance increases by a factor K (dielectric constant of dielectrics).

Since, the energy of the system is U₀ ($U_0=\frac{1}{2}C{V}^2$) so the new energy will become KU₀