A charged particle having a charge -2- 10-6 C is placed close to the non-conducting plate having a surface charge density 4- 10-6 Cm-2- The force of attraction between the particle and the plate is nearly -

The correct option is D 0.45 N #10; #10; #10; #10; #10; #10; #10; #10; #10; #10; #10; #10; #10; #10; #10; #10; #10;The ...

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Standard XII

Physics

Infinite Sheet

A charged par...

Question

A charged particle having a charge $- 2 \times 10^{- 6} C$ is placed close to the non-conducting plate having a surface charge density $4 \times 10^{- 6} C m^{- 2}$ . The force of attraction between the particle and the plate is nearly :

0.9 N

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0.71 N

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0.62 N

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0.45 N

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Solution

The correct option is D $0.45 N$

The electric field due to the plate is $E = \frac{σ}{2 ϵ_{0}}$

Here the force between the charged particle of charge q and the plate is

$F = q E = \frac{q σ}{2 ϵ_{0}} = \frac{2 \times 10^{- 6} \times 4 \times 10^{- 6}}{2 \times 8.854 \times 10^{- 12}} = 0.45 N$

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A charged particle having a charge −2×10−6C is placed close to the non-conducting plate having a surface charge density 4×10−6Cm−2. The force of attraction between the particle and the plate is nearly :

The correct option is D 0.45N The electric field due to the plate is E=σ2ϵ0 Here the force between the charged particle of charge q and the plate is F=qE=qσ2ϵ0=2×10−6×4×10−62×8.854×10−12=0.45N

A charged particle having a charge $- 2 \times 10^{- 6} C$ is placed close to the non-conducting plate having a surface charge density $4 \times 10^{- 6} C m^{- 2}$ . The force of attraction between the particle and the plate is nearly :