Question

A charged particle is moved along the magnetic field lines. The magnetic force on the particle is -

• A. along its velocity
• B. opposite to its velocity
• C. perpendicular to its velocity
• D. zero

Answer 1

The correct option is D zero

We know that, magnetic force,

${\overrightarrow{F}}_m=q\overrightarrow{v}\times \overrightarrow{B}$

So, $F=qvB\sin \theta$

As the charged particle is moved along the magnetic field lines, $\theta =0^{\circ }$.

Hence, $F=0$