Question

A charged spherical conductor of radius a and charge $q$, is surrounded by another charged concentric sphere of radius $b(b>a)$. The potential difference between conductors is $V$. When, the spherical conductor of radius b is discharged completely, then the potential difference between conductor will be :

• A. $V$
• B. $\frac{v_a}{b}$
• C. $\frac{q_1}{4\pi {\epsilon }_{0}a}-\frac{q_2}{4\pi {\epsilon }_{0}b}$
• D. None of the above

Answer 1

Answer: (A)

$V$

Since in inner sphere no change in charge is seen so there will not be any change in electric field between the inner and outer sphere therefore no change of voltage is seen between them.

Hence, voltage between them is $V$.