Question

A child has a die whose 6 faces show the letters given below:

$\boxed{\mathrm{A}}\boxed{\mathrm{B}}\boxed{\mathrm{C}}\boxed{\mathrm{A}}\boxed{\mathrm{D}}\boxed{\mathrm{A}}$

The die is thrown once. What is the probability of getting (i) A, (ii) D?

Answer 1

(i) The probability of getting A = P(A) = $\frac{\mathrm{number}\mathrm{of}\mathrm{favorable}\mathrm{outcomes}}{\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{possible}\mathrm{outcomes}}=\frac{3}{6}=\frac{1}{2}.$

(ii) The probability of getting D = P(D) = $\frac{\mathrm{number}\mathrm{of}\mathrm{favorable}\mathrm{outcomes}}{\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{possible}\mathrm{outcomes}}=\frac{1}{6}.$