Question

# A child has a die whose six faces show the letters as given below: The die is thrown once. What is the probability of getting $A$ $A,B,C,D,E,A$

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Solution

## The total number of possible outcomes (or events) $=6$$P\left(E\right)=\frac{Numberoffavourableoutcomes}{Totalnumberofoutcomes}$The total number of faces having $A$on it $=2$Probability (getting $A$) $=\frac{2}{6}=\frac{1}{3}=0.33$Hence, the he probability of getting $A$ is $0.33.$

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