Question

A child has die whose 6 faces show the letters given below.

A

B

C

A

A

B

The die is thrown once. What is the probability of getting (i) A, (ii) B?

Answer 1

When the die is thrown once, then any one of the six faces can show up.

∴ Total number of outcomes = 6

(i) There are 3 faces on the die showing the letter A.

Favourable number of outcomes = 3

∴ P(Getting the letter A) = $\frac{\mathrm{Favourable}\mathrm{number}\mathrm{of}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}=\frac{3}{6}=\frac{1}{2}$

(ii) There are 2 faces on the die showing the letter B.

Favourable number of outcomes = 2

∴ P(Getting the letter B) = $\frac{\mathrm{Favourable}\mathrm{number}\mathrm{of}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}=\frac{2}{6}=\frac{1}{3}$