Question

A chime is made of 3 identical spherical balls of density 363 g/$c{m}^3$. If mass of each ball is 49 g, then find radius of each ball.
Take $\pi =\frac{22}{7}$

• A. $\frac{7}{22}$ cm
• B. $\frac{22}{7}$ cm
• C. $\frac{1}{21}$ cm
• D. $\frac{2}{7}$ cm

Answer 1

The correct option is A

$\frac{7}{22}$ cm

Given,
density of spherical ball = 363 g/cm${}^3$ and mass of spherical ball = 49 g

We know that,
$\text{Volume of the ball}=\frac{\text{Mass of the ball}}{\text{density of ball}}$
And volume of a sphere of radius 'r' is given by $\frac{4}{3}\pi r^3$.

$\therefore \frac{4}{3}\pi r^3=\frac{49}{363}$

$\Rightarrow r^3=\frac{49\times 3}{363\times 4\times \pi }\Rightarrow r^3=\frac{49\times 3\times 7}{363\times 4\times 22}=\frac{7^3}{{22}^3}\Rightarrow r=\frac{7}{22}cm$
Therefore, radius of the identical spherical balls is $\frac{7}{22}cm$.