A spherical ball made of iron has diameter 6 cm. If density of iron 8g/ $c m^{3}$ then mass of the ball is nearly (use $π = 3.142$ )

0.9 kg

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0.8 kg

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0.7 kg

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0.62 kg

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Solution

The correct option is A 0.9 kg
Volume of ball
V = $\frac{4}{3} \times 3.14 \times 3 \times 3 \times 3 c m^{3} = 113.04 m^{3}$
Mass of ball = vol x density
= 113.04 x 8 g = 904.32 g = 0.9 kg

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A spherical ball made of iron has diameter 6 cm. If density of iron 8g/cm3 then mass of the ball is nearly (use π=3.142)

The correct option is A 0.9 kgVolume of ballV = 43×3.14×3×3×3cm3=113.04m3Mass of ball = vol x density = 113.04 x 8 g = 904.32 g = 0.9 kg

A spherical ball made of iron has diameter 6 cm. If density of iron 8g/ $c m^{3}$ then mass of the ball is nearly (use $π = 3.142$ )

The correct option is A 0.9 kg
Volume of ball
V = $\frac{4}{3} \times 3.14 \times 3 \times 3 \times 3 c m^{3} = 113.04 m^{3}$
Mass of ball = vol x density
= 113.04 x 8 g = 904.32 g = 0.9 kg