Question

A chloride of an element contains $49.5$% chlorine. The specific heat of the element is $0.056$. Calculate the equivalent mass, valency and atomic mass of the element.

Answer 1

The mass of chlorine in metal chloride is given= 49.5%

Therefore the mass of metal= (100-49.5) = 50.5

The equalent mass of metal is given by the formula:

$\frac{massofmetal}{massofchlorine}\times 35.5$

$\frac{50.5}{49.5}\times 35.5=36.21$

According to dulong pettits law:

atomic mass of metal=$\frac{6.4}{specificheat}$

= $\frac{6.4}{0.056}\times 114.3$

= $\frac{atomicmass}{equivalentmass}$

= $\frac{114.3}{36.21}=3.1g$

Hence, 3.1g is the answer.The mass of chlorine in metal chloride is given= 49.5%

therefore the mass of metal= (100-49.5) = 50.5

The equivalent mass of metal is given by the formula:

= $\frac{massofmetal}{massofchlorine}\times 35.5$

=$\frac{50.5}{49.5}\times 35.5=36.21$

According to dulong pettits law:

atomic mass of metal=$\frac{6.4}{specificheat}$

= $\frac{6.4}{0.056}\times 114.3$

= $\frac{atomicmass}{equivalentmass}$

= $\frac{114.3}{36.21}=3.1g$

Hence, 3.1g is the answer.