Question

A chord AB of a circle of radius 20 cm makes a right angle at the centre of the circle
What is the area of the minor segment in $c{m}^2?$
Take $\pi =\mathrm{3.14.}$

• A. $31.4$
• B. $57$
• C. $62.8$
• D. $314$

Answer 1

Answer: (D)

$314$

Let AB be cord and O is the centre of circle

So radius AO+BO=20 cm

Then area of minor sector =$\frac{\theta }{360}\times \pi r^2=\frac{90}{60}\times 3.14\times (20{)}^2=\frac{1}{4}\times 3.14\times 400=314c{m}^2$