Question

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

(i) Minor segment

(ii) Major sector

[Use π = 3.14]

Answer 1

Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OADB =

Area of minor sector OACB =

Area of ΔOAB =

= 50 cm²

Area of minor segment ACB = Area of minor sector OACB −

Area of ΔOAB = 78.5 − 50 = 28.5 cm²