1
Question
A circle of radius 3 cm, with centre O is drawn circumscribing a ΔABC. What is the sum of OA + OB + OC?
A circle of radius 3 cm, with centre O is drawn circumscribing a ΔABC. What is the sum of OA + OB + OC?
Open in App
Solution
The correct option is C 9 cm
Given, radius = 3 cm.
Therefore the distance of A from the centre O is 3 cm.
Similarly the distance of B from O and the distance of C from O are 3 cm each.
Thus, r = OA = OB = OC = 3 cm.
Hence, OA + OB + OC = 3 + 3 + 3 = 9 cm.
9 cm
Given, radius = 3 cm.
Therefore the distance of A from the centre O is 3 cm.
Similarly the distance of B from O and the distance of C from O are 3 cm each.
Thus, r = OA = OB = OC = 3 cm.
Hence, OA + OB + OC = 3 + 3 + 3 = 9 cm.
Suggest Corrections
0
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
