Since the radius of the circle is 3 cm, we have OA = OB = OC = 3 cm.
Hence, OA + OB + OC = 3 cm + 3 cm + 3 cm = 9 cm.
A circle of radius 3 cm, with centre O is drawn circumscribing a ΔABC. What is the sum of OA + OB + OC ?