A circle passes through (0, 0) and (1, 0) and touches the circle $x^{2} + y^{2} = 9$ , then the centre of circle is

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Solution

The correct option is D

Radius of the circle r = $\frac{3}{2}$

$\frac{1}{4} + k^{2} = \frac{9}{4} \Rightarrow k = \pm \sqrt{2}$

Hence centre is $(\frac{1}{2}, \pm \sqrt{2})$ .

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