Question

A circle passes through the points $(0,0)$ and $(0,1)$ and also touches the circle $x^2+y^2=16$. The radius of the circle is

• A. 1
• B. 2
• C. 3
• D. 4
• E. 5

Answer 1

Answer: (B)

2

As $(0,0)$ and $(0,1)$ lies inside the circle $x^2+y^2=16$ .

So the circle will touch the given circle internally.

And by symmetry its diameter will be equal to given radius of given circle.

Radius of given circle $=\sqrt{16}=4$

So radius of our circle $=\frac{4}{2}=2$

So, option B is correct.