Question

A circle $S=0$ is drawn with its centre at $(-1,1)$ so as to touch the circle $x^2+y^2-4x+6y-3=0$ externally. Find the intercept made by the circle $S=0$ on the coordinates axes.

• A. $0,0$
• B. $1,2$
• C. $0,1$
• D. $1,0$

Answer 1

Answer: (A)

$0,0$

let the radius of the circle be $r$
Since, they touch each other externally
Then, $C_1{C}_2=r_1+r_2$
$\Rightarrow \sqrt{{(-1-2)}^2+{(1+3)}^2}=r+4$
$\Rightarrow r=1$
Therefore, equation of circle is ${(x+1)}^2+{(y-1)}^2=1$
which touches both the co-ordinate axis
Therefore, both the intercept are zero
Ans: A