A circuit has a fuse of $5 A$ . What is the maximum number of $100 W (220 V)$ bulbs that can be safely used in the circuit?

11

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Solution

The correct option is A $11$
Total power flow through the fuse , $P = V I$
$= 220 \times 5 = 1100 W$
Power consumed by one bulb, $P_{1} = 100 W$
Number of bulbs required to consume a total power of $1100 W$ is
$P = n \times P_{1}$
$n = \frac{1100}{100} = 11$

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A circuit has a fuse of 5 A. What is the maximum number of 100 W(220 V) bulbs that can be safely used in the circuit?

The correct option is A 11Total power flow through the fuse , P=VI =220×5=1100 W Power consumed by one bulb, P1=100 W Number of bulbs required to consume a total power of 1100 W is P=n×P1 n=1100100=11

A circuit has a fuse of $5 A$ . What is the maximum number of $100 W (220 V)$ bulbs that can be safely used in the circuit?

The correct option is A $11$
Total power flow through the fuse , $P = V I$
$= 220 \times 5 = 1100 W$
Power consumed by one bulb, $P_{1} = 100 W$
Number of bulbs required to consume a total power of $1100 W$ is
$P = n \times P_{1}$
$n = \frac{1100}{100} = 11$