A circular coil of 1 turn and area 0.01m carries a current of 10A. It is placed in a uniform magnetic field of induction 0.1T such that the plane of the circle is perpendicular to the direction of the field, the torque acting on the coil is
A
0.1Nm
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B
0.001Nm
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C
0.01Nm
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D
0
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Solution
The correct option is D0 Magnetic moment vector is parallel to that of field. Hence, Torque =→M×→B=Q