A circular coil of 20 cm 2 area is made of 100 turns as shown is figure- In 0-2 sec of time- B reverses its direction of the field- How much charge flows through wire- if R -6 - - B -4-8 TeskB- 0-32 C C- 0-28 CD- 0-64 C

The correct option is B 0.32 CEMF = N ( Δϕ/Δ t ) i = EMF/R = N/R ( Δϕ/Δ t ) Charge flown through R nbsp; = Δ q = i Δ t = N Δϕ/R = 100 × (9.6) × 20 × 10/R ...

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Standard XII

Physics

Using Lenz's Law

A circular co...

Question

A circular coil of $20 c m^{2}$ area is made of 100 turns as shown is figure. In 0.2 sec of time, $\to B$ reverses its direction of the field. How much charge flows through wire, if R = 6 $Ω$ ?

0.32 C

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0.64 C

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0.28 C

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0.16 C

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Solution

The correct option is A 0.32 C
$E M F = N (\frac{Δ ϕ}{Δ t}) i = \frac{E M F}{R} = \frac{N}{R} (\frac{Δ ϕ}{Δ t})$
Charge flown through $R = Δ q = i Δ t$
$= \frac{N Δ ϕ}{R} = \frac{100 \times (9.6) \times 20 \times 10}{R}$
$= \frac{100 \times 2 \times 4.8 \times 20 \times 10^{- 4}}{R}$
$= \frac{19.2 \times 10^{- 1}}{6} = 0.32 C$

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A circular coil of 20cm2 area is made of 100 turns as shown is figure. In 0.2 sec of time, →B reverses its direction of the field. How much charge flows through wire, if R = 6 Ω?

The correct option is A 0.32 CEMF=N(ΔϕΔt)i=EMFR=NR(ΔϕΔt) Charge flown through R=Δq=iΔt =NΔϕR=100×(9.6)×20×10R =100×2×4.8×20×10−4R =19.2×10−16=0.32 C

A circular coil of $20 c m^{2}$ area is made of 100 turns as shown is figure. In 0.2 sec of time, $\to B$ reverses its direction of the field. How much charge flows through wire, if R = 6 $Ω$ ?