A circular coil of radius 4 cm and 20 turns carries a current of 3 ampere. It is placed in a magnetic field of 0.5 T. The magnitude of magnetic dipole moment of the coil will be?

0.60 A - m^{2}

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0.45 A - m^{2}

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0.3 A - m^{2}

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0.15 A - m^{2}

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Solution

The correct option is C $0.3 A - m^{2}$
$M = n i A \Rightarrow M = 20 \times 3 \times π (4 \times 10^{- 2})^{2} = 0.3 A - m^{2}$ .

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A circular coil of radius 4 cm and 20 turns carries a current of 3 ampere. It is placed in a magnetic field of 0.5 T. The magnitude of magnetic dipole moment of the coil will be?

The correct option is C 0.3A−m2M=niA⇒M=20×3×π(4×10−2)2=0.3A−m2.

The correct option is C $0.3 A - m^{2}$
$M = n i A \Rightarrow M = 20 \times 3 \times π (4 \times 10^{- 2})^{2} = 0.3 A - m^{2}$ .