Question

A circular shaft, 50 mm in diameter is welded to the support using circumferential fillet weld. It is subjected to a torsional moment of 2500 N-m. What is the minimum size of the weld, if permissible shear stress in the world is limited to 140 $N/m{m}^2$?

• A. 14 mm
• B. 10 mm
• C. 5 mm
• D. 7 mm

Answer 1

The correct option is D 7 mm

$\tau =\frac{M_t}{2\pi t{r}^2}$


$140=\frac{2500\times 1000}{2\pi \times t(25{)}^2}$

t = 4.55 mm

$\text{Size of weld, h =}\frac{t}{0.707}=6.43mm$

h = 7 mm