Question

A circular track has a circumference of 3140 m with AB as one of its diameter shooter moves from A to B along the circular path with a uniform speed of 10

• A. Distance covers by the scooter
• B. Displacement of scooters
• C. Time taken by the scooter in maching from A to B
• D. None of these

Answer 1

The correct option is A Distance covers by the scooter

Given,

Circumference of circular track$=2\pi r=3140$m where $r=$radius of circle

Now according to question,Scooter moves from $A$ to $B$ along the circular path (where $AB$ is diameter).

It means scooter completes half a revolution(circumference/2).

So,Distance travelled$=$The actual path traversed by scooter$=\frac{3140}{2}=1570$ m

Again,Displacement$=$The shortest distance travelled by scooter(Final position$-$Initial position)

$=$Diameter of the circle$=2r$

Since $2\pi r=3140$m (here$\pi =3.14$)

$2r=\frac{3140}{3.14}=1000$ m.

To calculate the time taken by the scooter in reaching from $A$ to $B$,we have a formula

Speed$=\frac{Distance}{Time}$

Time$=\frac{Distance}{Speed}=\frac{1570}{10}=157$ seconds.