A circus is cylindrical to a height of 3 metres and conical above it. If its diameter is 105 m and the slat height of the conical portion is 53 m, calculate the length of the canvas 5 m wide to make the required tent.

Open in App

Solution

Height = h = 3 metres

Slant height = l = 53 metres

Radius = r = 52.5 metres

Area of canvas required = C.S.A of cone = πrl
= 22/7 ×52.5 ×53

= 8745 m²

Suggest Corrections

Similar questions

Q. A circus tent is cylindrical to a height of 3 metres and conical above it. If its diameter is 105 m and the slant height of the conical portion is 53 m, calculate the length of the canvas 5 m wide to make the required tent.

Q. A circus tent is cylindrical up to a height of

3 m

and conical above it If its diameter is

105 m

and slant height of the conical portion is

53 m

then area of canvas needed to build the tent is:

Q. A circus tent is cylindrical up to a height of

3 m

and conical above. If the diameter of the base is

105 m

and the slant height of the conical part is

53 m

, find the total canvas used in making the tent.

Q. A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, find the area of canvas needed to make the tent.

A circus tent is cylindrical to a height of 4 m and conical above it. If its diameter is 105 m and its slant height is 80 m, calculate the total area of canvas required. Also, find the total cost of canvas used at Rs.15 per metre if the width is 1.5 m.

Join BYJU'S Learning Program

A circus is cylindrical to a height of 3 metres and conical above it. If its diameter is 105 m and the slat height of the conical portion is 53 m, calculate the length of the canvas 5 m wide to make the required tent.

Height = h = 3 metres Slant height = l = 53 metres Radius = r = 52.5 metres Area of canvas required = C.S.A of cone = πrl = 22/7 ×52.5 ×53 = 8745 m²

Height = h = 3 metres

Slant height = l = 53 metres

Radius = r = 52.5 metres

Area of canvas required = C.S.A of cone = πrl
= 22/7 ×52.5 ×53

= 8745 m²