A circus tent is cylindrical up to a height of $3 m$ and conical above it If its diameter is $105 m$ and slant height of the conical portion is $53 m$ then area of canvas needed to build the tent is:

9730 m^{2}

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9736 m^{2}

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9790 m^{2}

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9735 m^{2}

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Solution

The correct option is D $9735 m^{2}$
Area of canvas $=$ CSA of cyl $+$ CSA of cone
$= π r l + 2 π r H$
$= π r (l + 2 H)$
$= \frac{22}{7} \times \frac{105}{2} (53 + 6) m^{2}$
$= 9735 m^{2}$

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and conical above. If the diameter of the base is

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and the slant height of the conical part is

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, find the total canvas used in making the tent.

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π = 22 / 7

) :

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A circus tent is cylindrical up to a height of 3 m and conical above it If its diameter is 105 m and slant height of the conical portion is 53 m then area of canvas needed to build the tent is:

The correct option is D 9735 m2Area of canvas = CSA of cyl + CSA of cone =πrl+2πrH =πr(l+2H) =227×1052(53+6)m2 =9735 m2

A circus tent is cylindrical up to a height of $3 m$ and conical above it If its diameter is $105 m$ and slant height of the conical portion is $53 m$ then area of canvas needed to build the tent is:

The correct option is D $9735 m^{2}$
Area of canvas $=$ CSA of cyl $+$ CSA of cone
$= π r l + 2 π r H$
$= π r (l + 2 H)$
$= \frac{22}{7} \times \frac{105}{2} (53 + 6) m^{2}$
$= 9735 m^{2}$