Question

A circus tent is cylindrical to a height of 6 m and conical above it. If its diameter is 105 m and slant height of the conical portion is 50 m then the total area of canvas required to build the tent is (Use $\pi =22/7$) :

• A. 10230 $m^2$
• B. 11230 $m^2$
• C. 14230 $m^2$
• D. 12340 $m^2$

Answer 1

The correct option is A 10230 $m^2$

The tent has two parts
(I) a cylindrical part and (II) a conical part
(I) curved surface area of cylindrical portion
$=2\pi rh$
$2\times \frac{22}{7}\times \frac{105}{2}\times 6m^2$
=1980 $m^2$
(II) Curved sufrace area of conical portion
$\pi rl$
$\frac{22}{7}\times \frac{105}{2}\times 50m^2$
$=8250m^2$
$\therefore$ Total area of canvas required to build the tent
=Curved surface area of conical portion
$=1980m^2+8250m^2=10230m^2$