Question

A circus tent is cylindrical to a height of 3 m and conical above it. If its base radius is 52.5 m and the slant height of the conical portion is 53 m, find the area of canvas needed to make the tent.

Answer 1

Radius of the cylinder = 52.5 m
Radius of the base of the cone = 52.5 m
Slant height (l) of the cone = 53 m
Height of the cylinder (h) = 3 m
Curved surface area of the cylindrical portion$=2\pi rh=\left(2\times \frac{22}{7}\times 52.5\times 3\right){\mathrm{m}}^2=990{\mathrm{m}}^2$
Curved surface area of the conical portion$=\pi rl=\left(\frac{22}{7}\times 52.5\times 53\right){\mathrm{m}}^2=8745{\mathrm{m}}^2$

Thus, the total area of canvas required for making the tent$=\left(8745+990\right){\mathrm{m}}^2=9735{\mathrm{m}}^2$