A circus tent is cylindrical to a height of 3 meters and conical above it.If its diameter is 105 m and the slant height of the conical portion is 53 m, calculate the length of the canvas 5 m wide to make the required tent.

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Solution

Diameter of the cylindrical tent = 105 m

$∴ R a d i u s (r) = \frac{105}{2} m$

Height of the cylindrical portion $h_{1}$ =3 m

and slant height of the conical portion=53 m

$∴ T o t a l s u r f a c e a r e a o f t h e t e n t = π r l + 2 π r h = π r (l + 2 h) = \frac{22}{7} \times \frac{105}{2} (53 + 2 \times 3) m^{2}$

$= 165 (53 + 6) m^{2} = 165 \times 59 m^{2} = 9735 m^{2} B r e a d t h o f c a n v a s u s e d = 5 m ∴ L e n g t h = \frac{A r e a}{B r e a d t h} = \frac{9735}{5} m = 1947 m$

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