Question

A circus tent is cylindrical to a height of 8 m surmounted by a conical part. If total height of the tent is 13 m and the diameter of its base is 24 m; calculate: (i) total surface area of the tent, (ii) area of canvas, required to make this tent allowing 10% of the canvas used for folds and stitching.

Answer 1

We have the following situation-

1) Total surface area of tent

$=2\pi rh+\pi rl=\pi r(2h+l)=\frac{22}{7}(16+13)12=1093.71m^2$

2)Total area of canvas required

= Surface area of tent + 10% of the Surface area of the tent

=1093.71 + 109.37

=1203 sq metre