A circus tent is cylindrical to a height of $8$ m surmounted by a conical part. If total height of the tent is $13$ m and the diameter of its base is $24$ m; calculate area of canvas, required to make this tent allowing $10 %$ of the canvas used for folds and stitching.

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Solution

Area of canvas used in stitching = total area of canvas
Total area of canvas $= 7656 / 7$ + total area of canvas/10
Total area of canvas – Total area of canvas/10 $= 7656 / 10$
Total area of canvas $(1 - \frac{1}{10}) = \frac{7656}{7}$
Total area of canvas $\times \frac{9}{10} = \frac{7656}{7}$
Total area of canvas $= \frac{7656}{7} \times \frac{10}{9} = \frac{76560}{63}$
Therefore, the total area of canvas $= 1215.23 m^{2}$

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