A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

90 cm

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10 cm

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20 cm

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15 cm

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Solution

The correct option is B 10 cm
Let the thickness of the bottom be x cm.
Then,
$[(330 - 10) \times (260 - 10) \times (110 - x)] = 8000 \times 1000$
[ $∵$ the wall is 5 cm thick on each side and $1 l = 1000 c m^{3}$
$\Rightarrow 320 \times 250 \times (110 - x) = 8000 \times 1000 \Rightarrow (110 - x) = \frac{8000 \times 1000}{320 \times 250} \Rightarrow x = 10 c m$

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A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:

The correct option is B 10 cmLet the thickness of the bottom be x cm. Then, [(330−10)×(260−10)×(110−x)]=8000×1000 [∵ the wall is 5 cm thick on each side and 1l=1000cm3 ⇒320×250×(110−x)=8000×1000⇒(110−x)=8000×1000320×250⇒x=10 cm