A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. Calculate the thickness of the bottom.

15 cm

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10 cm

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12 cm

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25 cm

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Solution

The correct option is B
10 cm

Let the thickness of the bottom be $x$ cm.
Then,
$[(330 - 10) \times (260 - 10) \times (110 - x)] = 8000 \times 1000$

$Since the wall is 5 cm thick on each side and 1 l = 1000 c m^{3},$
$320 \times 250 \times (110 - x) = 8000 \times 1000$
$\Rightarrow (110 - x) = \frac{8000 \times 1000}{320 \times 250}$
$\Rightarrow 110 - x = 100$
$\Rightarrow x = 10 c m$

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A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. Calculate the thickness of the bottom.

The correct option is B 10 cm Let the thickness of the bottom be x cm. Then, [(330−10)×(260−10)×(110−x)]=8000×1000 Since the wall is 5 cm thick on each side and 1 l=1000cm3, 320×250×(110−x)=8000×1000 ⇒(110−x)=8000×1000320×250 ⇒110−x=100 ⇒x=10 cm